CogLabThe Cognition Lab

Physics simulations

Materials Atlas · physics workbench

Model. Compare. Investigate.

Work from molecular geometry, crystal structure, processing conditions or a material stack. Inspect the physics, compare calculated results, and turn uncertainty into the next research question.

01 Define the system02 Review the method03 Calculate & check04 Compare & decide
Define your calculation

Heat through a layered material

Calculate steady heat flow, interface temperature jumps and the resistance of each layer.

Scientific inputs
Layers, from hot to cold
Interface conductanceW/m²/KConductance belongs to each adjacent pair. Supply a value for every new contact.
Method scope & sources

One-dimensional steady conduction with specified layer conductivities and interface conductances.

  • Constant conductivity and interface conductance
  • No internal heat generation, lateral heat loss or radiation
  • Input coefficients must match the material and temperature conditions

MIT heat transfer course ↗

Calculated result

Equal Layers

Model calculation
Area-normalized thermal resistance0.000201m² K/W
Steady heat flux497,510W/m²
Stack effective conductivity9.9502W/(m K)
Interface share of resistance0.0049751
Temperature (K)
40003750.00053500.0013250.00153000.002
Depth (m)
Through-thickness temperature
Depth: 0 m · Temperature: 400 K

Interpret the result

  • One-dimensional steady Fourier conduction; constant cross-sectional area.
  • Conductivity and interface conductance are supplied inputs at the modeled conditions, not inferred from a material name.
  • No internal heat generation, lateral loss, radiation or ballistic transport.
Numerical checks & provenance
Hot-to-cold temperature closure0 ≤ 1E-7 K
Independent node-balance solution2.8422E-13 ≤ 1E-6 K

Passing these checks verifies the stated numerical properties. Agreement with experiment requires a separate, condition-matched comparison.

Input SHA-256: 79fb6cd1976f5e253cf6e06b51ce91318e85d10d635f440d12a77f83cdb84be3
Runner SHA-256: f27376d0f80371a1da4c926f1a21d43d841802e9f87bac7e876738ea78181e3d
atlas 1 · python 3.14.10 · numpy 2.5.4 · scipy 1.18.1
Calculated 11/12/2026, 2:03:23 AM · 0.0013179 s

Test the explanation

Compare a numerical refinement or a different physical assumption. Agreement within one model does not establish agreement with experiment.

Build the investigation

Bring the observable, conditions and result into a research plan with competing hypotheses and a test that can distinguish them.

Investigate this result →